Monthly Mathematics: Group theory and Topology
This is an idea that popped into my mind a while back that I’ve really wanted to make a thing. I think the monthly mathematics could be a really useful facility for skeptics to practice critical thinking skills and logic. As a skeptic, I believe critical thinking is a corner stone of what it means to be a skeptic. We don’t accept things on face value, and, ideally, question our most core of values to ensure accuracy. What does it mean to think critically though? Critical thinking, to me, seems to be an umbrella term for applying various forms of rigor in our evaluation of questions and statements about various topics. I think logic is at the core of all of the forms of rigor we apply. Mathematics is, in essence, applied logic. It is for these reasons that I am inclined to believe that practicing mathematics can benefit skeptics. Also, math is objectively—yes, objectively—fun!
Monthly Mathematics post’s aim is to facilitate such practice. In each post, I will provide math problems of various difficulties that will require a proof; this will not be a place for simple calculation, and solving the problems might take some time. Before the questions are posed, I will provide relevant definitions and theorems in hopes of providing the basic framework for thinking about the problem. These questions will not come out of a book; they will, instead, try to force the reader to connect various concepts from different fields within mathematics. The questions might be true or false, and I will provide the answers to the problems in the next post with the names of the people who got a question right first. I will also be open to suggestions for problems. Suggestions would actually be very helpful because I am a pure mathematician, and don’t have much training or interest in applied mathematics.
Don’t be afraid to be wrong! There is no shame in it, and you might even inspire someone else to get the right answer. For example, last night I gave a 2 hour talk in a hyperspace seminar, and one of my proofs was wrong. There was a gab in my argument, but I was close enough to the answer that we were able to fix it on the fly. No one shamed or laughed at me, and I didn’t let it throw me off. It was a learning exercise, and I won’t make a similar mistake again, hopefully. So, I encourage you to post your thoughts even if they aren’t completely correct or finished.
With the preliminaries out of the way, let’s give this a go. This month we will be looking at a mix of basic group theory and topology.
I have some strong opinions on mathematical notation; accordingly, my notation isn’t always standard. I will clarify notation in each post that isn’t standard, or that may be unclear. The only non-standard bit of notation is this post is my symbol for “such that:” |. I use the pipe because I find it to be more clear and consistent. I also use a slightly different notation within the conditions of a set. It is as follows: ( statement )[ conditions ], and is read as “statement such that conditions.”
Topological space: A topological space (X, T) is an ordered pair where X is some set, and where T is a set of subsets of X that meet the following conditions:
2. T is closed with respect to finite and infinite unions, i.e. if , then
3. T is closed with respect to finite intersections, i.e .
Open set: U is said to be an open set of the topological space iff
Point: x is said to be a point of the topological space iff
Base for a topology: The statement that , where , is a basis for (X, T) means that if and then and
Group: A group is a set G paired with a binary operation, *, such that the following properties hold with respect to the operation
3. Identify element:
4. inverse elements:
Subgroup: Let G be some group, and . U is a subgroup of G iff U is a group with respect to the same operation as G.
Normal subgroup: Let G be some group, and . N is said to be a normal subgroup of G iff —note this is normal multiplication, cosets to be exact, here, and not the operation defined on the group.
1. If (X, T) is a topological space and is a basis for T, then .
2. Let X be a set and be a collection of subsets of X. is a basis for a topology on X iff the following conditions hold:
- if U and V are sets in , and , then
Let G be some finite group. Does the set of normal subgroups form a topology?
Does the set of normal subgroups, for some finite group G, form a base for a topology?